Chapter
14 Practice Questions Answers
14.148
ANSWER:
(a)
Po = 0.50
(b)
r
= 0.50
(c)
L = 1
(d)
Lq = 0.50
(e)
W = 0.0667 hours
(f)
Wq = 0.0333 hours
14.151
ANSWER:
(a)
Po = 0.5
(b)
r =
0.5
(c)
L = 1
(d)
Lq = 0.5
(e)
Wq = 0.05 hours
(f)
W = 0.1 hours
14.153
ANSWER:
(a)
r =
0.500
(b)
Wq = 0.25 time units (minutes)
(c)
Lq = 0.500
14.159
ANSWER:
(a)
Po = 0.167
(b)
r
= 0.833
(c)
L = 5
(d)
Lq = 4.167
(e)
W = 0.2 hours = 12 minutes
(f)
Wq = 0.167 hours = 10
minutes
14.162
ANSWER:
(a)
r
= 0.833
(b)
Wq = 0.833 hours = 50 minutes
(c)
P(more than three students waiting) = P(more than four students in
system) = 0.402
(d)
P(someone will have to stand) = P(more than five students in system) =
0.335
14.163 ANSWER:
(a)
0.8
(b)
3.2
(c)
The average time waiting is 0.33 hours (or 20 minutes) so this will
likely be a problem.
14.161
ANSWER:
(a) r
= 0.833
(b) Lq
= 3.788
(c) Wq = 0.152 hours or 9.09 minutes
(d) Yes, he has met that goal: time spent being served:
0.066 hours; time spent waiting: 0.152 hours.
(e) Utilization factor is 0.833. Utilized time =
0.833(8 hours per day)(2 workers) = 13.33 hours
Nonutilized time in hours is given by: 16 – 13.33 = 2.67 hours @ 160
minutes.
He did not meet this goal.
(f) Arrival rate would have to be approximately 27.2 persons per hour.